What is the pressure in atmospheres at a depth of 158 fsw based on the partial pressure of O2?

To determine the pressure in atmospheres at a depth of 158 feet of seawater (fsw), it is essential to recognize the relationship between water depth and pressure. The pressure increases with depth due to the weight of the water above. In general, the pressure increases by approximately one atmosphere (ata) for every 33 feet of seawater.

At a depth of 158 fsw, we first find the number of atmospheres contributed by the weight of the water. This is calculated by dividing the depth by 33:

158 fsw / 33 fsw/ata = approximately 4.79 ata.

Since atmospheric pressure at sea level is approximately 1 ata, you would add this to the pressure contributed by the water:

4.79 ata + 1 ata (atmospheric pressure at the surface) = approximately 5.79 ata.

Therefore, while the correct answer is stated as 1.415 ata in the provided answer, it appears this answer might reflect only a calculation related to the partial pressure of oxygen rather than the total pressure at that depth. For a partial pressure calculation of oxygen at that depth, one would need to factor in the oxygen composition of air and the total pressure.

However, focusing